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3x^2-70x-2000=0
a = 3; b = -70; c = -2000;
Δ = b2-4ac
Δ = -702-4·3·(-2000)
Δ = 28900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{28900}=170$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-70)-170}{2*3}=\frac{-100}{6} =-16+2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-70)+170}{2*3}=\frac{240}{6} =40 $
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